9x^2-124=0

Solution for 9x^2-124=0 equation:

9x^2-124=0

a = 9; b = 0; c = -124;
Δ = b2-4ac
Δ = 02-4·9·(-124)
Δ = 4464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4464}=\sqrt{144*31}=\sqrt{144}*\sqrt{31}=12\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{31}}{2*9}=\frac{0-12\sqrt{31}}{18}
=-\frac{12\sqrt{31}}{18}
=-\frac{2\sqrt{31}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{31}}{2*9}=\frac{0+12\sqrt{31}}{18}
=\frac{12\sqrt{31}}{18}
=\frac{2\sqrt{31}}{3}
$